A bag contains 1 blue, 2 green, and 3 red marbles, as shown. What is the probability of drawing a green marble out of the bag without looking?

Accepted Solution

ANSWER[tex] P(G)= \frac{1}{3}[/tex]EXPLANATIONThe number of green marbles in the bag is [tex]n(G) = 2[/tex]The total number of marbles in the bag is [tex]n(S)=1+2+3 = 6[/tex]The probability of selecting a green marble from the bag without looking is [tex]P(G)= \frac{n(G)}{n(S)} [/tex]Substitute the values to get,[tex]P(G)= \frac{2}{6} [/tex][tex]P(G)= \frac{1}{3} [/tex]